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Chemistry Question on General Principles and Processes of Isolation of Elements

Hall-Heroult's process is given by :

A

Cr2O3+2Al−>Al2O3+2Cr{Cr2O3 + 2Al -> Al2O3 + 2Cr}

B

Cu2+(a)+H2(g)→Cu(s)+2H+(aq){Cu^{2+} (a) + H_2(g) \to Cu(s) + 2H^{+} (aq)}

C

ZnO+C−>[Coke,1673K]Zn+CO{ZnO + C ->[Coke, 1673 K] Zn + CO}

D

2Al2O3+3C→4Al+3CO2{2 Al_2 O_3 + 3C \to 4Al + 3CO_2 }

Answer

2Al2O3+3C→4Al+3CO2{2 Al_2 O_3 + 3C \to 4Al + 3CO_2 }

Explanation

Solution

In Hall-Heroult's process is given by
2Al2O3+3C−>4Al+3CO2{2Al2O3 + 3C -> 4Al + 3CO2}
2Al2O3(ℓ)<=>4Al3+(ℓ)+6O2⊖(ℓ){2Al2O3(\ell) <=> 4Al^{3+}(\ell) + 6O^{2 \ominus}(\ell)}
At  cathode:−4Al(ℓ)3++12eominus−>4Al(ℓ){At \; cathode :- 4Al^{3 +}_{(\ell)} + 12 e^{ominus} -> 4Al(\ell)}
At  Anode:6O(ℓ)2⊖−>3O2(g)+12e⊖{At \; Anode : 6O^{2 \ominus}_{(\ell)} -> 3O_2 (g) + 12e^{\ominus}}
3C+3O2−>3CO1(){3C + 3O_2 -> 3CO_1 (^)}