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Question

Physics Question on Thermodynamics

Half mole of an ideal monoatomic gas is heated at constant pressure of 1 atm from 20C20{^{\circ}C} to 90C90^{\circ}C. Work done by gas is close to : ( Gas constant R = 8.31J/molK8.31\, J\, /mol-K)

A

73 J

B

291 J

C

581 J

D

146 J

Answer

291 J

Explanation

Solution

WD=PΔV=nRΔT=12×8.31×70WD = P\Delta V =nR\Delta T = \frac{1}{2} \times8.31 \times70