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Question

Physics Question on Half life

Half lives of two radioactive substances A and B are respectively 20 minute and 40 minute. Initially the sample of A and B have equal number of nuclei. After 80 minutes, the ratio remains in number of A and B nuclei is.

A

4:01

B

1:16

C

1:01

D

1:04

Answer

1:04

Explanation

Solution

From the relation NN0=12n\frac{N}{{{N}_{0}}}=\frac{1}{{{2}^{n}}} so N12nN\propto \frac{1}{{{2}^{n}}} Hence, NANB=1/241/22=124×221=14\frac{{{N}_{A}}}{{{N}_{B}}}=\frac{1/{{2}^{4}}}{1/{{2}^{2}}}=\frac{1}{{{2}^{4}}}\times \frac{{{2}^{2}}}{1}=\frac{1}{4}