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Question

Chemistry Question on Chemical Kinetics

Half-lives of a first order and a zero order reactions are same. Then, the ratio of the initial rates of first order reaction to that of the zero order reaction is

A

10.93\frac{1}{0.93}

B

2×0.6932\times 0.693

C

0.6930.693

D

20.693\frac{2}{0.693}

Answer

2×0.6932\times 0.693

Explanation

Solution

t1/2{{t}_{1/2}} for zero order reaction
=[A]02k=\frac{{{[A]}_{0}}}{2k}
t1/2{{t}_{1/2}} for first order reaction
=0.693k=\frac{0.693}{k} Rate of zero order reaction,
r0=k[A]02.t1/2{{r}_{0}}=k\frac{{{[A]}_{0}}}{2.{{t}_{1/2}}} Rate of first order reaction,
r1=k(A0)=0.693t1/2[A]0{{r}_{1}}=k({{A}_{0}})=\frac{0.693}{{{t}_{1/2}}}{{[A]}_{0}}
\Rightarrow r1r0=0.693[A]0t1/2×2×t1/2[A]0\frac{{{r}_{1}}}{{{r}_{0}}}=\frac{0.693{{[A]}_{0}}}{{{t}_{1/2}}}\times \frac{2\times {{t}_{1/2}}}{{{[A]}_{0}}}
=2×0.693=2\times 0.693