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Chemistry Question on Chemical Kinetics

Half-life period of a first order reaction is 1386 s.1386\, s. The specific rate constant of the reaction is

A

5.0×10−3s−15.0 \times 10^{-3} s^{-1}

B

0.5×10−2s−10.5 \times 10^{-2} s^{-1}

C

0.5×10−3s−10.5 \times 10^{-3} s^{-1}

D

5.0×10−2s−15.0 \times 10^{-2} s^{-1}

Answer

0.5×10−3s−10.5 \times 10^{-3} s^{-1}

Explanation

Solution

K=0.693t1/2=0.6931386=0.5×10−3S−1K =\frac{0.693}{ t _{1 / 2}}=\frac{0.693}{1386}=0.5 \times 10^{-3} S ^{-1}