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Question: Hailstone at 0°C falls from a height of 1 km on an insulating surface converting whole of its kineti...

Hailstone at 0°C falls from a height of 1 km on an insulating surface converting whole of its kinetic energy into heat. What part of it will melt (g=10m/s2)(g = 10m/s^{2})

A

133\frac{1}{33}

B

18\frac{1}{8}

C

133×10−4\frac{1}{33} \times 10^{- 4}

D

All of it will melt

Answer

133\frac{1}{33}

Explanation

Solution

Suppose m′ kg ice melts out of m kg then by using

W=JQW = JQ ⇒ mgh=J(m′L)mgh = J(m^{'}L).

Hence fraction of ice melts

=m′m=ghJL=9.8×10004.18×80=133= \frac{m^{'}}{m} = \frac{gh}{JL} = \frac{9.8 \times 1000}{4.18 \times 80} = \frac{1}{33}