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Question: \(H_{2}O_{2} \rightarrow 2H^{+} + O_{2} + 2e^{-}\); \(E{^\circ} = - 0.68V\). This equation represen...

H2O2→2H++O2+2e−H_{2}O_{2} \rightarrow 2H^{+} + O_{2} + 2e^{-}; E∘=−0.68VE{^\circ} = - 0.68V.

This equation represents which of the following behaviour of H2O2H_{2}O_{2}.

A

Reducing

B

Oxidising

C

Acidic

D

Catalytic

Answer

Reducing

Explanation

Solution

As H2O2H_{2}O_{2} is loosing electrons so it is acting as reducing agent.