(H\_{2}O\_{2}) reduces(Mn{O\_{4}}^{-})ion to. | CHEMISTRY - REDOX REACTIONS IN TERMS OF ELECTRON TRANSFER REACTIONS | SolveeIt

$H_{2}O_{2}$ reduces $Mn{O_{4}}^{-}$ ion to.

$Mn^{+}$

$Mn^{2 +}$

$Mn^{3 +}$

$Mn^{-}$

Answer

$Mn^{2 +}$

Explanation

$2MnO_{4}^{\Theta} + 5H_{2}O_{2} + 6H^{+} \rightarrow Mn^{2 +} + 5O_{2} + 8H_{2}O$ .

Question: \(H_{2}O_{2}\) reduces\(Mn{O_{4}}^{-}\)ion to....