(H\_2O) is polar, whereas (BeF\_2) is not because | Chemistry | SolveeIt

Question

$H_2O$ is polar, whereas $BeF_2$ is not because

electronegativity of F is greater than that of O

$H_2O$ involves H-bonding, whereas $BeF_2$ is not a discrete molecule

$H_2O$ involves H-bonding, whereas $BeF_2$ is a discrete molecule

$H_2O$ is linear and $BeF_2$ is angular.

Answer

$H_2O$ is linear and $BeF_2$ is angular.

Explanation

Solution

Because of linear shape, dipole moments cancel each other in BeF (F $\overline{ ? }$ Be $\overline{\mapsto}$ F) and thus, it is non-polar, whereas HO is V-shaped and hence, it is polar.

Chemistry Question on Chemical bonding and molecular structure

Solution