Question

$H_2O_2$ behave like reducing agent in which of the following reactions:

• A. $Fe^{+2}+ H_2O_2 → Fe^{+3} + H_2O$
• B. $H_2S+H_2O_2 → SO^{2-}_4+H_2O$
• C. $HOCl + H_2O_2 → Cl^- + 2H_2O + O_2$
• D. $Mn^{+2} + H_2O_2 → MnO_2 + H_2O$

Answer 1

Answer: (C)

$HOCl + H_2O_2 → Cl^- + 2H_2O + O_2$

Answer 2

$H_2O_2$ reduces $HOCl$ to $Cl^-$ and itself gets oxidised to $O_2.$

The correct option is (c ): $HOCl + H_2O_2 → Cl^- + 2H_2O + O_2$