Question

${{H}_{2}}O$ is dipolar, whereas $Be{{F}_{2}}$ is not. It is because

• A. the electronegativity of $F$ is greater than that of $O$
• B. ${{H}_{2}}O$ involves hydrogen bonding whereas $Be{{F}_{2}}$ is a discrete molecule
• C. ${{H}_{2}}O$ is linear and $Be{{F}_{2}}$ is angular
• D. ${{H}_{2}}O$ is angular and $Be{{F}_{2}}$ is linear

Answer 1

Answer: (D)

${{H}_{2}}O$ is angular and $Be{{F}_{2}}$ is linear

Answer 2

The structure of $H _{2} O$ is angular V-shape and has $s p^{3}$-hybridisation and bond angle is $105^{\circ}$. Its dipole moment value is positive or more than zero. but in $BeF _{2}$, structure is linear due to $s p$ hybridisation $(\mu=0)$ Thus, due to $\mu>0, H _{2} O$ is dipolar and due to $\mu=0, BeF _{2}$ is non-polar.