Question

$H _2 O _2$ acts as a reducing agent in

• A. $Na _2 S +4 H _2 O _2 \rightarrow Na _2 SO _4+4 H _2 O$
• B. $Mn ^{2+}+2 H _2 O _2 \rightarrow MnO _2+2 H _2 O$
• C. $2 Fe ^{2+}+2 H ^{+}+ H _2 O _2 \rightarrow 2 Fe ^{3+}+2 H _2 O$
• D. $2 NaOCl + H _2 O _2 \rightarrow 2 NaCl + H _2 O + O _2$

Answer 1

Answer: (D)

$2 NaOCl + H _2 O _2 \rightarrow 2 NaCl + H _2 O + O _2$

Answer 2

Correct answer is (d) 2NaOCl+H2​O2​→2NaCl+H2​O+O2​