Question
Question: Find the equation of the chord of contact of the point (1, 2) with respect to the circle $x^2 + y^2 ...
Find the equation of the chord of contact of the point (1, 2) with respect to the circle x2+y2+2x+3y+1=0.

Answer
The equation of the chord of contact is 4x+7y+10=0.
Explanation
Solution
The equation of the given circle is x2+y2+2x+3y+1=0. Comparing this with the general form x2+y2+2gx+2fy+c=0, we get g=1, f=3/2, and c=1. The given point is (x1,y1)=(1,2). The equation of the chord of contact is given by T=0, where T=xx1+yy1+g(x+x1)+f(y+y1)+c. Substituting the values: T=x(1)+y(2)+1(x+1)+23(y+2)+1 T=x+2y+x+1+23y+3+1 T=2x+27y+5 Setting T=0: 2x+27y+5=0 Multiplying by 2 to remove the fraction: 4x+7y+10=0