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Question

Question: Find the equation of the chord of contact of the point (1, 2) with respect to the circle $x^2 + y^2 ...

Find the equation of the chord of contact of the point (1, 2) with respect to the circle x2+y2+2x+3y+1=0x^2 + y^2 + 2x + 3y + 1 = 0.

Answer

The equation of the chord of contact is 4x+7y+10=04x + 7y + 10 = 0.

Explanation

Solution

The equation of the given circle is x2+y2+2x+3y+1=0x^2 + y^2 + 2x + 3y + 1 = 0. Comparing this with the general form x2+y2+2gx+2fy+c=0x^2 + y^2 + 2gx + 2fy + c = 0, we get g=1g = 1, f=3/2f = 3/2, and c=1c = 1. The given point is (x1,y1)=(1,2)(x_1, y_1) = (1, 2). The equation of the chord of contact is given by T=0T=0, where T=xx1+yy1+g(x+x1)+f(y+y1)+cT = xx_1 + yy_1 + g(x+x_1) + f(y+y_1) + c. Substituting the values: T=x(1)+y(2)+1(x+1)+32(y+2)+1T = x(1) + y(2) + 1(x+1) + \frac{3}{2}(y+2) + 1 T=x+2y+x+1+32y+3+1T = x + 2y + x + 1 + \frac{3}{2}y + 3 + 1 T=2x+72y+5T = 2x + \frac{7}{2}y + 5 Setting T=0T=0: 2x+72y+5=02x + \frac{7}{2}y + 5 = 0 Multiplying by 2 to remove the fraction: 4x+7y+10=04x + 7y + 10 = 0