Question

Glucose when treated with CH3OH in presence of dry HCl gas gives a- and b- methylglucosides because it contains

• A. An aldehydic group
• B. A – CH2OH group
• C. A ring structure
• D. Five – OH group

Answer 1

Answer: (C)

A ring structure

Answer 2

$\alpha$ and $\beta$ methyl glucosides are formed because glucose contains a ring structure and the reaction with CH3OH passes through a carbanion.