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Question: Glucose reduces Fehling's solution to: (A) Copper (B) Black cupric oxide (C) Reddish-brown cu...

Glucose reduces Fehling's solution to:
(A) Copper
(B) Black cupric oxide
(C) Reddish-brown cuprous oxide
(D) Mixture of copper and cupric oxide

Explanation

Solution

Fehling’s solution is used to differentiate between the reducing and non-reducing sugar. If the sugar on reduction with Fehling’s forms a precipitate then the sugar is a reducing sugar if does not form the ppt then it is a non-reducing sugar.

Complete step by step answer:
Carbohydrates are of two types: reducing and non-reducing sugar. The reducing sugar, when treated with Fehling’s solution, forms a precipitate. This is because reducing sugar has a free aldehyde or ketone group.
Let us see the reduction of Fehling’s solution by glucose: Fehling’s solution is an alkaline solution of CuSO4CuS{{O}_{4}}containing some Rochelle salt, i.e., sodium potassium tartrate and is prepared by adding an alkaline solution of Rochelle salt (called Fehling's solution 'B') to an aqueous solution of CuSO4CuS{{O}_{4}}(called Fehling’s solution ‘A’) until blue ppt. of Cu(OH)2Cu{{(OH)}_{2}}first formed just redissolves to form a clear deep blue solution. When an aliphatic aldehyde or ketone is heated with Fehling's solution, the latter is reduced to give a reddish-brown ppt of cuprous oxide. During the reduction, the reaction which occurs is:
RCHO+2Cu2++5OHRCOO+Cu2O+3H2ORCHO+2C{{u}^{2+}}+5O{{H}^{-}}\to RCO{{O}^{-}}+C{{u}_{2}}O\downarrow +3{{H}_{2}}O
The formula of glucose is CH2OH(CHOH)4CHOC{{H}_{2}}OH{{(CHOH)}_{4}}CHO. So, when the glucose reacts with Fehling’s solution it forms red ppt and gluconic acid. The reaction is given:
CH2OH(CHOH)4CHO+2CuOCH2OH(CHOH)4COOH+Cu2O(red ppt.)C{{H}_{2}}OH{{(CHOH)}_{4}}CHO+2CuO\to C{{H}_{2}}OH{{(CHOH)}_{4}}COOH+C{{u}_{2}}O(red\text{ }ppt.).
Non-reducing sugars do not have free aldehydes or ketone groups, hence they do not give Fehling's solution test.

Hence, the correct answer is an option (c)- Reddish-brown cuprous oxide.

Note: All the monosaccharides gives the Fehling’s solution test. All polysaccharides are non-reducing sugars. The glucose and monosaccharides give another test called Tollen’s reagent test in which they form a silver mirror.