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Question: Glucose is converted into ethyl alcohol in the presence of the enzyme a.) Invertase b.) Zymase ...

Glucose is converted into ethyl alcohol in the presence of the enzyme
a.) Invertase
b.) Zymase
c.) Diastase
d.) All above

Explanation

Solution

Hint: In order to solve this question, we need to figure out the conditions in which the conversion of glucose to ethyl alcohol, will take place. Once we are done with the criteria, we can compare the enzyme used in the reaction with the options given.

Complete step-by-step answer:
Here is the equation for the conversion of glucose into ethyl alcohol.

C6H12O6(aq) Zymase 2C2H5OH(aq) + 2CO2(g)  Glucose Ethyl alcohol Carbon dioxide \begin{aligned} & {{\text{C}}_{\text{6}}}{{\text{H}}_{\text{12}}}{{\text{O}}_{\text{6}}}\left( \text{aq} \right)\text{ }\xrightarrow{\text{Zymase}}\text{ 2}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}\text{OH}\left( \text{aq} \right)\text{ + 2C}{{\text{O}}_{\text{2}}}\left( \text{g} \right) \\\ & \text{ Glucose Ethyl alcohol Carbon dioxide} \\\ \end{aligned}

From the diagram, we can see that the enzyme that is used in the conversion of glucose into ethyl alcohol is Zymase.
Zymase is an enzyme complex that catalysts the fermentation of sugar into ethanol and carbon dioxide. It occurs naturally in yeasts. Zymase activity varies among yeast strains. Zymase is also the brand name of the drug pancrelipase.
Buchner proved that fermentation does not require intact yeast cells, but is caused by an enzyme called zymase. Pyrazole belongs to a class of organic compounds of the heterocyclic series with 5 - membered ring structure.
So, we can say that Glucose is converted into ethyl alcohol in the presence of the enzyme is Zymase. Therefore, the correct option is Option B.

Note: We should have a basic idea of glucose. Here are some important points about glucose:
Glucose is the most abundant monosaccharide, which is a subcategory of carbohydrates.
Glucose is the main type of sugar in the blood and is the main source of energy for the body's cells.