Question

Glucose gives silver mirror with ammoniacal silver nitrate because it has

• A. aldehyde group
• B. ester group
• C. ketone group
• D. alcoholic silver nitrate

Answer 1

Answer: (A)

aldehyde group

Answer 2

Glucose gives silver mirror with ammoniacal silver nitrate due to the presence of -CHO group (aldehyde group) in the structure of glucose.

$CH_2 OH(CHOH)_4 CHO + Ag_2 O \longrightarrow$

$\underset {\text{gluconic acid}}{CH_2 OH(CHOH)_4} - COOH + \underset {\text{silver mirror}}{2Ag \downarrow}$