Question
Question: Given X = a<sup>n</sup>b<sup>m</sup>/p<sup>r</sup>. The percent error in measurement of a, b and p i...
Given X = anbm/pr. The percent error in measurement of a, b and p is 1%, 0.5% and 0.75% respectively. If n = 2, m = 2 and r = 4 then percent error in x is
A
0
B
6 %
C
5.25%
D
0.75 %
Answer
6 %
Explanation
Solution
XdX×100=(nada+mbdb+rpdp)×100 = 2 × 1 + 2(0.5) + 4(0.75) = 6%