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Question

Question: Given X = a<sup>n</sup>b<sup>m</sup>/p<sup>r</sup>. The percent error in measurement of a, b and p i...

Given X = anbm/pr. The percent error in measurement of a, b and p is 1%, 0.5% and 0.75% respectively. If n = 2, m = 2 and r = 4 then percent error in x is

A

0

B

6 %

C

5.25%

D

0.75 %

Answer

6 %

Explanation

Solution

dXX×100=(ndaa+mdbb+rdpp)×100\frac{dX}{X} \times 100 = \left( n\frac{da}{a} + m\frac{db}{b} + r\frac{dp}{p} \right) \times 100 = 2 × 1 + 2(0.5) + 4(0.75) = 6%