Question
Question: Given vectors **a**, **b**, **c** such that \(\mathbf{a}.(\mathbf{b} \times \mathbf{c}) = \lambda \n...
Given vectors a, b, c such that a.(b×c)=λ=0, the value of (b×c).(a+b+c)/λ is
A
3
B
1
C
−3λ
D
3/λ
Answer
1
Explanation
Solution
λ(b×c).(a+b+c)=λ(b×c).a+(b×c).b+(b×c).c
=λ(b×c).a+0+0=λλ=1,
(∵Givena.(b×c)=λ=(b×c).a).