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Question: Given two mutually exclusive events A and B such that \(P ( A ) = 0.45\) and \(P ( B ) = 0.35\) ...

Given two mutually exclusive events A and B such that P(A)=0.45P ( A ) = 0.45 and P(B)=0.35P ( B ) = 0.35 then P (A or B) =

A

0.1

B

0.25

C

0.15

D

0.8

Answer

0.8

Explanation

Solution

P(A∪B)=P(A)+P(B)P ( A \cup B ) = P ( A ) + P ( B ) = 0.45+0.35=0.80.45 + 0.35 = 0.8