Solveeit Logo

Question

Mathematics Question on Three Dimensional Geometry

Given the points A(6,7,0),B(16,19,4),C(0,3,6)A(6,-7,0),B(16,-19,-4),C(0,3,-6) and D(2,5,10)D(2,-5,10),the point of intersection of the lines ABAB and CDCD is

A

(1,1,2)(-1,1,2)

B

(1,1,2)(1,-1,2)

C

(1,1,2)(1,-1,-2)

D

(1,1,2)(-1,1,-2)

E

(1,1,2)(1,1,2)

Answer

(1,1,2)(1,-1,2)

Explanation

Solution

Given that

A(6,7,0),B(16,19,4),C(0,3,6)A(6,-7,0),B(16,-19,-4),C(0,3,-6) and D(2,5,10)D(2,-5,10) are the point of intersection of the lines ABAB and CDCD
So, the point f intersection can be found as ,
Any point on ABAB can be written as (6+5x,76x,2x)(6+5x,−7−6x,−2x)
Any point on CDCD can be written as (y,34y,6+8y)(y,3−4y,−6+8y)
To find the intersection of ABAB and CDCD , the coordinates of the point written in the two different ways should be equal.
Hence,
6+5x=y6+5x=y
76x=34y−7−6x=3−4y
2x=6+8y−2x=−6+8y
The three equations are consistent and on solving we get: x=1x=−1 and y=1y=1.
Hence, desired point of intersection is (1,1,2)(1,−1,2).
So, the correct option is (B) : (1,1,2)(1,−1,2)