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Question

Question: Given the matrix: $\begin{pmatrix} 3 & 5 & 2 \\ 1 & 4 & 6 \\ 7 & 0 & 8 \end{pmatrix}$ Find the min...

Given the matrix:

(352146708)\begin{pmatrix} 3 & 5 & 2 \\ 1 & 4 & 6 \\ 7 & 0 & 8 \end{pmatrix}

Find the minor corresponding to the element in the 2nd row and 3rd column, and then determine its cofactor.

Answer

Minor corresponding to element at (2,3): -35

Cofactor corresponding to element at (2,3): 35

Explanation

Solution

Solution:

  1. Finding the Minor:
    For element a23=6a_{23} = 6 (2nd row, 3rd column), remove the 2nd row and 3rd column to obtain the 2×22 \times 2 matrix:

    (3570)\begin{pmatrix} 3 & 5 \\ 7 & 0 \end{pmatrix}

    Its determinant (the minor) is:

    M23=3×07×5=35.M_{23} = 3 \times 0 - 7 \times 5 = -35.
  2. Finding the Cofactor:
    The cofactor is given by:

    C23=(1)2+3×M23=(1)5×(35)=(35)=35.C_{23} = (-1)^{2+3} \times M_{23} = (-1)^5 \times (-35) = -(-35) = 35.

Explanation (Minimal Core):
Remove row 2 and column 3, compute the determinant det(3570)=35\det\begin{pmatrix} 3 & 5 \\ 7 & 0 \end{pmatrix} = -35 for the minor, and then multiply by (1)2+3=1(-1)^{2+3} = -1 to get the cofactor 3535.