Question

Given the following values for an elastic material Young's modulus = 7 × 10¹⁰ Nm^–2 and Bulk modulus = 11 × 10¹⁰ Nm^–2. The Poisson's ratio of the material is –

• A. 0.12
• B. 0.24
• C. 0.31
• D. 0.39

Answer 1

Answer: (D)

0.39

Answer 2

K = $\frac{Y}{3(1 - 2\sigma)}$ or 11 × 10¹⁰ = $\frac{7 \times 10^{10}}{3(1 - 2\sigma)}$

or $\frac{7}{33}$ = 1– 2s or 2s = 1 – $\frac{7}{33}$

s = $\frac{26}{33}$ = 0.39