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Question: Given that \(\overset{\rightarrow}{A} + \overset{\rightarrow}{B} + \overset{\rightarrow}{C}\)= 0 out...

Given that A+B+C\overset{\rightarrow}{A} + \overset{\rightarrow}{B} + \overset{\rightarrow}{C}= 0 out of three vectors two are equal in magnitude and the magnitude of third vector is 2\sqrt{2} times that of either of the two having equal magnitude. Then the angles between vectors are given by

A

300, 600, 900

B

450, 450, 900

C

450, 600, 9000

D

900, 1350, 1350

Answer

900, 1350, 1350

Explanation

Solution

From polygon law, three vectors having summation zero should form a closed polygon. (Triangle) since the two vectors are having same magnitude and the third vector is 2\sqrt{2} times that of either of two having equal magnitude. i.e. the triangle should be right angled triangle

Angle between A and B, α = 900

Angle between B and C, β = 1350

Angle between A and C, γ = 1350