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Question: Given that one root is \(3\) times the others for the quadratic equation \(3{x^2} - 2x + p = 0\), fi...

Given that one root is 33 times the others for the quadratic equation 3x22x+p=03{x^2} - 2x + p = 0, find (a) the value of p and (b) the two roots?

Explanation

Solution

In this question, we are dealing with quadratic equations. So, there are two equations relating the roots with constant and coefficient terms as α+β=ba\alpha + \beta = \dfrac{{ - b}}{a} and αβ=ca\alpha \beta = \dfrac{c}{a} for the standard equation ax2+bx+c=0a{x^2} + bx + c = 0. Also, there is a relation between the two roots in the above question. So, we can also write one root in terms of another.

Complete step-by-step answer:
In the above question, it is given that one root is 33 times the others for the quadratic equation 3x22x+p=03{x^2} - 2x + p = 0.
Let one root of the quadratic equation be x.
Then the second root be 3x3x.
We know that α+β=ba\alpha + \beta = \dfrac{{ - b}}{a} and αβ=ca\alpha \beta = \dfrac{c}{a} for the standard equation ax2+bx+c=0a{x^2} + bx + c = 0.
On comparing the standard equation with the given equation, we get
a=3,b=2,c=pa = 3,\,b = - 2,\,\,c = p and let α=x\alpha = x , β=3x\beta = 3x.
α+β=ba\alpha + \beta = \dfrac{{ - b}}{a}
On putting the values in above equation, we get
x+3x=(2)3x + 3x = \dfrac{{ - \left( { - 2} \right)}}{3}
4x=23\Rightarrow 4x = \dfrac{2}{3}
Divide both sides by 22.
2x=13\Rightarrow 2x = \dfrac{1}{3}
Now, on doing cross-multiplication, we get
x=16\Rightarrow x = \dfrac{1}{6}

(a) Now, we will find the value of p in this part.
αβ=ca\alpha \beta = \dfrac{c}{a}
Now, put the values in above equation
(3x)(x)=p3\left( {3x} \right)\left( x \right) = \dfrac{p}{3}
3x2=p3\Rightarrow 3{x^2} = \dfrac{p}{3}
p=9x2\Rightarrow p = 9{x^2}
Now, put the value of x=16x = \dfrac{1}{6} in the above equation.
p=9(16)2\Rightarrow p = 9{\left( {\dfrac{1}{6}} \right)^2}
p=9×136\Rightarrow p = 9 \times \dfrac{1}{{36}}
p=14\Rightarrow p = \dfrac{1}{4}
Therefore, the value of p is 14\dfrac{1}{4}.

(b) Now, in this part we will find the value of two roots.
First root =x=16 = x = \dfrac{1}{6}.
Second root =3x=3×16=12 = \,3x = 3 \times \dfrac{1}{6} = \dfrac{1}{2}
Therefore, the value of two roots are 16and12\dfrac{1}{6}\,and\,\dfrac{1}{2}.

Note: We can also find the roots of a quadratic equation using quadratic formula. From that formula we get two values of x which we can relate with the help of the condition given in the question and therefore we can find the value of p in the above question.