Question
Question: Given that one root is \(3\) times the others for the quadratic equation \(3{x^2} - 2x + p = 0\), fi...
Given that one root is 3 times the others for the quadratic equation 3x2−2x+p=0, find (a) the value of p and (b) the two roots?
Solution
In this question, we are dealing with quadratic equations. So, there are two equations relating the roots with constant and coefficient terms as α+β=a−b and αβ=ac for the standard equation ax2+bx+c=0. Also, there is a relation between the two roots in the above question. So, we can also write one root in terms of another.
Complete step-by-step answer:
In the above question, it is given that one root is 3 times the others for the quadratic equation 3x2−2x+p=0.
Let one root of the quadratic equation be x.
Then the second root be 3x.
We know that α+β=a−b and αβ=ac for the standard equation ax2+bx+c=0.
On comparing the standard equation with the given equation, we get
a=3,b=−2,c=p and let α=x , β=3x.
α+β=a−b
On putting the values in above equation, we get
x+3x=3−(−2)
⇒4x=32
Divide both sides by 2.
⇒2x=31
Now, on doing cross-multiplication, we get
⇒x=61
(a) Now, we will find the value of p in this part.
αβ=ac
Now, put the values in above equation
(3x)(x)=3p
⇒3x2=3p
⇒p=9x2
Now, put the value of x=61 in the above equation.
⇒p=9(61)2
⇒p=9×361
⇒p=41
Therefore, the value of p is 41.
(b) Now, in this part we will find the value of two roots.
First root =x=61.
Second root =3x=3×61=21
Therefore, the value of two roots are 61and21.
Note: We can also find the roots of a quadratic equation using quadratic formula. From that formula we get two values of x which we can relate with the help of the condition given in the question and therefore we can find the value of p in the above question.