Question
Question: Given, \({{\text{H}}_{\text{2}}}\text{S}\) contains 5.88% hydrogen, \({{\text{H}}_{\text{2}}}\text{O...
Given, H2S contains 5.88% hydrogen, H2O contains 11.11% hydrogen while SO2 contains 50% sulphur. These figures illustrate the law of:
(A) conservation of mass
(B) constant proportions
(C) multiple proportions
(D) reciprocal proportions
Solution
Find out the molecular weight of each compound. Recollect the basic laws of chemical combination.
Complete answer:
-According to the law of definite proportions, “Any pure compound always contains the same elements in a definite proportion by weight irrespective of its source or method of preparation.” This law was given by French chemist, Joseph Proust. It is also known as the law of constant proportions.
-The molecular weight of H2S is equal to 34g/mol. There are two hydrogen atoms, so the mass of hydrogen in H2S is 2g. So, the amount of hydrogen present in H2S is 342×100=5.88
-Similarly, let's calculate hydrogen in water. The molecular weight of H2O is 18g. There are two hydrogen atoms, so the mass of hydrogen in H2O is 2g. So, the amount of hydrogen present in H2O is 182×100=11.11
-In the same manner, let us calculate sulphur in sulphur dioxide,SO2. The molecular weight of SO2 is 64g. There is one sulphur atom present in SO2. So, the mass of sulphur is 32g. Therefore, the amount of sulphur present in SO2 is 6432×100=50
-Thus, we can conclude that the given figures illustrate the law of constant proportions.
So, the correct option is (B) constant proportions.
Note:
Don’t get confused with other laws of combination like law of conservation of mass and law of multiple proportions. The law of multiple proportions talks about finding the ratios of masses of two or more elements of the compound in smaller numbers instead of the percentage proportion of each element in the compound.