Question

Given :$\overset{\rightarrow}{A}$= $\widehat{i}$+ 2$\widehat{j}$– 3$\widehat{k}$. When a vector $\overset{\rightarrow}{B}$is added to $\overset{\rightarrow}{A}$, we get a unit vector along X-axis. Then, $\overset{\rightarrow}{B}$ is -

• A. – 2$\widehat{j}$ + 3$\widehat{k}$
• B. –$\widehat{i}$ – 2$\widehat{j}$
• C. –$\widehat{i}$+ 3$\widehat{k}$
• D. 2$\widehat{j}$ – 3$\widehat{k}$

Answer 1

Answer: (A)

– 2$\widehat{j}$ + 3$\widehat{k}$

Answer 2

($\widehat{i}$+ 2$\widehat{j}$– 3$\widehat{k}$) + $\overset{\rightarrow}{B}$=$\widehat{i}$

$\overset{\rightarrow}{B}$= – 2$\widehat{j}$+ 3$\widehat{k}$