Question
Question: Given,\(Na\) and \(Mg\) crystallize in BCC and FCC type crystals respectively, then the number of at...
Given,Na and Mg crystallize in BCC and FCC type crystals respectively, then the number of atoms of Na and Mg present in the unit cell of their respective crystal is:
a) 4 and 2
b) 9 and 14
c) 14 and 9
d) 2 and 4
Solution
Atoms in the body centered cubic lattice are present in the eight corners and in the body centre whereas atoms in the face centered lattice are present in the eight corners and in the centre of the six faces.
Complete step by step answer:
In a body centered cubic lattice the atoms are placed in the eight corners and one atom is present in the centre of the body.
The packing efficiency of body centered cubic lattice is 68%. The contributions of atoms in the body centered cubic lattice can also be determined. The contribution of each corner atom is one-eighth and the contribution of the atom present in the body centre is one.
⇒no.ofatoms×contribution ⇒8×81+1×1 ⇒2
Hence the total number of Na will be 8corners+1bodycentre=9atoms.
In a face centered cubic lattice the atoms are placed in the eight corners and six atoms are in the centre of the six faces of the cube.
The packing efficiency of body centered cubic lattice is 74%. The contributions of atoms in the body centered cubic lattice can also be determined. The contribution of each corner atom is one-eighth and the contribution of the atom present in face centre is half.
⇒no.ofatoms×contribution ⇒8×81+6×21 ⇒4
Hence the total number of Mg will be 8corners+6facecentre=14atoms.
So the correct option is (b).
Note:
As the packing efficiency of a crystal lattice increases, the stability and availability of such crystal lattices increases in nature. As compared to BCC more FCC lattices are available in nature. Also FCC lattices have tetrahedral and octahedral voids.