Question

Given:
(i) Cu2++2e−→Cu,E0=0.337 V
(ii) Cu2++e−→Cu+,E0=0.153
Standard electrode potential, E∘ for the reaction, Cu+e−→Cu, will be (in volts):

Answer 1

Explanation:
We know that, ΔG∘=−nFE∘
So for the reaction, Cu2++2e−→CuΔG∘=2×F×0.337…(1)
For the reaction, Cu+→Cu2++e−ΔG∘=1×F×0.153…(2)
So adding both the equations, we get
Cu++e−→Cu;
ΔG∘=−0.521 F
ΔG∘=−nFE∘
⇒ΔE∘=0.52 V
Hence, the correct answer is 0.52 V.