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Question: Given \(f\left( x \right) = 4x - 3,g\left( x \right) = \dfrac{1}{x}\) and \(h\left( x \right) = {x^2...

Given f(x)=4x3,g(x)=1xf\left( x \right) = 4x - 3,g\left( x \right) = \dfrac{1}{x} and h(x)=x2xh\left( x \right) = {x^2} - x. How do you find h(kx)?h\left( {kx} \right)?

Explanation

Solution

In this question, we are going to solve and find the value of h(kx)h\left( {kx} \right) and xx
First we are going to write the given terms and then substitute x=kxx = kx in the expression h(x)h\left( x \right), we get a value.
Then simplify the terms by equating it to zero, we can get the value of xx
Hence we can get the required solution.

Complete step by step solution:
In this question, we are going to find the value of h(kx)h\left( {kx} \right).
First we are going to write the given equation: f(x)=4x3f\left( x \right) = 4x - 3, g(x)=1xg\left( x \right) = \dfrac{1}{x}and h(x)=x2xh\left( x \right) = {x^2} - x
Now we are going to substitute x=kxx = kx in the given expression h(x)h\left( x \right) and then we are going to solve the value,
h(x)=x2x\Rightarrow h\left( x \right) = {x^2} - x
We can express this as
h(kx)=(kx)2kx\Rightarrow h\left( {kx} \right) = {\left( {kx} \right)^2} - kx
Squaring the first term we get,
h(kx)=k2x2kx\Rightarrow h\left( {kx} \right) = {k^2}{x^2} - kx
Thus we find the value of h(kx)h\left( {kx} \right) is k2x2kx{k^2}{x^2} - kx
We can take the like terms outside we get,
h(kx)=kx(kx1)\Rightarrow h\left( {kx} \right) = kx(kx - 1)

Therefore the value of h(kx)=kx(kx1)h\left( {kx} \right) = kx(kx - 1).

Note: Evaluating functions: To evaluate a function, substitute the input (the given number or expression) for the functions variable (placeholder, X). Replace the X with the number or expression.
A function rule describes how to convert an input value into an output value for a given function.
We need to have skills in evaluating functions:
We need the skill in evaluating a function to know how to replace its variable with a given number or expression.