Question
Question: Given \({E^{o}}_{Ag^{+}/Ag} = + 0.80V;{E^{o}}_{Cu^{2 +}/Cu} = + 0.34V;\) \({E^{o}}_{Fe^{3 +}Fe^{2 +...
Given EoAg+/Ag=+0.80V;EoCu2+/Cu=+0.34V;
EoFe3+Fe2+=+0.76V;EoCe4+/Ce3+=+1.60V
Which of the following statements is not correct?
A
Fe3+ does not oxidize Ce3+
B
Cu reduces Ag+to Ag.
C
Ag will reduce Cu2+to Cu.
D
Fe3+reduces Cu2+to Cu.
Answer
Ag will reduce Cu2+to Cu.
Explanation
Solution
: Since Ag has higher reduction potential than Cu, Ag will not reduce Cu2+to Cu. Cu can reduce Ag+ to Ag.