Question

Given : Electric potential at a point is : f = x²y + yz. The electric field at the point (1, 3, 1) is-

• A. 7 units
• B. 70 units
• C. 49 units
• D. 490 units

Answer 1

Answer: (A)

7 units

Answer 2

f = x²y + yz

E_x = – $\frac { \partial \phi } { \partial \mathrm { x } }$ = – 2xy

E_y = – $\frac { \partial \phi } { \partial y }$ = – x² –z

E_z = –= – y

at point (1,3,1), E = $\sqrt { 49 }$= 7