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Question

Question: Given : \[E_{Cr^{3 +}/Cr}^{0} = - 0.74V;E_{MnO_{4}^{-}/Mn^{2 +}}^{0} = 1.51V\] \(E_{Cr_{2}O_{7}^{2...

Given :

ECr3+/Cr0=−0.74V;EMnO4−/Mn2+0=1.51VE_{Cr^{3 +}/Cr}^{0} = - 0.74V;E_{MnO_{4}^{-}/Mn^{2 +}}^{0} = 1.51V

ECr2O72−/Cr3+0=1.33V;ECl/Cl−0=1.36VE_{Cr_{2}O_{7}^{2 -}/Cr^{3 +}}^{0} = 1.33V;E_{Cl/Cl^{-}}^{0} = 1.36VBased on the

data given above, strongest oxidising agent will be :

A

Cl

B

Cr3+

C

Mn2+

D

MnO4–

Answer

MnO4–

Explanation

Solution

Higher the SRP, better is oxidising agent

Hence MnO4- is strongest oxidising agent.