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Question

Chemistry Question on Redox reactions

Given ECl2/Cl=1.36V,ECr3+/Cr=774VE _{ Cl _{2} / Cl ^{-}}^{\circ}=1 . 36\, V,\, E _{ Cr ^{3+} / Cr }^{\circ}=-7 \cdot 74\, V ECr2O72/Cr3+=1.33V,EMnO4/Mn2+=1.51VE _{ Cr _{2} O _{7}^{2-} / Cr ^{3+}}^{\circ}=1 .33\, V,\, E _{ MnO _{4}^{-} / Mn ^{2}+}^{\circ}=1. 51\, V Among the following, the strongest reducing agent is:

A

Cr3+Cr^{3+}

B

ClCl^{-}

C

CrCr

D

Mn2+Mn^{2+}

Answer

CrCr

Explanation

Solution

For Cr3+,ECr3+/Cr2O72=1.33VCr ^{3+}, \,E _{ Cr ^{3+} / Cr _{2} O _{7}^{2-}}=-1.33\, V

For Cl,ECl/Cl2=1.36VCl ^{-}, \, E _{ Cl ^{-} / Cl _{2}}^{\circ}=-1.36\, V

For Cr,ECr/Cr3+=0.74VCr , \, E _{ Cr / Cr ^{3+}}^{\circ}=0.74\, V

For Mn2+,EMn2+/MnO4=1.51VMn ^{2+}, E _{ Mn ^{2+} / MnO _{4}^{-}}^{\circ}=-1.51\, V

Positive EE^{\circ} is for CrCr, hence it is strongest reducing agent.