Question
Chemistry Question on Redox reactions
Given ECl2/Cl−∘=1.36V,ECr3+/Cr∘=−7⋅74V ECr2O72−/Cr3+∘=1.33V,EMnO4−/Mn2+∘=1.51V Among the following, the strongest reducing agent is:
A
Cr3+
B
Cl−
C
Cr
D
Mn2+
Answer
Cr
Explanation
Solution
For Cr3+,ECr3+/Cr2O72−=−1.33V
For Cl−,ECl−/Cl2∘=−1.36V
For Cr,ECr/Cr3+∘=0.74V
For Mn2+,EMn2+/MnO4−∘=−1.51V
Positive E∘ is for Cr, hence it is strongest reducing agent.