Question

Given, $E^\circ _{Cr ^{3+}/Cr} =-0.74\, V;E^\circ_{MnO^-_4/Mn^{2+}}=1.51\, V$ $\, \, \, \, \, E^\circ _{Cr_2 O ^{2-}_7/Cr^{3+}} =-1.33\, V;E^\circ_{Cl/Cl^-}=1.36\, V$ Based on the data given above strongest oxidising agent will be

• A. $Cl$
• B. $Cr^{3+}$
• C. $Mn^{2+}$
• D. $MnO^-_4$

Answer 1

Answer: (D)

$MnO^-_4$

Answer 2

Higher the standard reduction potential, better is oxidising agent. Among the given $E^\circ_{MnO^-_4/Mn^{2+}}$ is highest $MnO^-_4$ is the strongest oxidising agent.