Question

Given $e = 2.72, e^2 =7.39 ,e^3 = 20.09 , e^4 = 54.60$ the approximate value of $\int\limits_{0}^{4} e^x dx$ using Simpson?? rule and taking $h=1$ is

• A. 57.325
• B. 53.873
• C. 58.325
• D. 57.323

Answer 1

Answer: (B)

53.873

Answer 2

$\int\limits_{0}^{4} f(x) \, dx \cong \frac{h}{3} [ (y_0 + y_4) +4 ( y_1 + y_3 ) + 2y_2 ] , h = 1$ .