Solveeit Logo
Login

Question

Question: Given data is at 25<sup>0</sup>C : \[\text{Ag}\text{ }^{+}\text{ }\text{I}^{-} \rightarrow \text{ ...

Given data is at 250C :

Ag + I−→ AgI + e− ; E0 = 0.152 VAg→ Ag+ + e− ; E0 = - 0.800 V\text{Ag}\text{ }^{+}\text{ }\text{I}^{-} \rightarrow \text{ AgI + }\text{e}^{-}\text{ ; }\text{E}^{0}\text{ = 0.152 V}\text{Ag} \rightarrow \text{ A}\text{g}^{+}\text{ + }\text{e}^{-}\text{ ; }\text{E}^{0}\text{ = - 0.800 V}

What is the value of log Ksp for AgI : (Take0.4740.059\frac{0.474}{0.059} = 8.065)

A

– 8.12

B
  • 8.612
C

– 37.83

D

– 16.13

Answer

– 16.13

Explanation

Solution

0.152 = - 0.8 - 0.0591 log KSPlog KSP = - 16.11.\text{0.152 = - 0.8 - }\frac{\text{0.059}}{1}\text{ log }\text{K}_{\text{SP}}\text{log }\text{K}_{\text{SP}}\text{ = - 16.11.}