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Question

Mathematics Question on Variance and Standard Deviation

Given data 60,60,44,58,68,α,β,5660, 60, 44, 58, 68, α, β, 56 has mean 5858, variance = 66.266.2, then find α2+β2α^2 + β^2.

Answer

The formula for Variance is:\text{The formula for Variance is:} x2n(xˉ)2\frac{\sum x^2}{n}-(\bar x)^2

Substituting the data given in the question, we find,\text{Substituting the data given in the question, we find,}

7200+1936+3364+4624+3136+α2+β283364\frac{7200+1936+3364+4624+3136+\alpha^2+\beta^2}{8}-3364 =66.2=66.2

2532.5+α2+β283364=66.22532.5+\frac{\alpha^2+\beta^2}{8}-3364=66.2

=7181.6=7181.6 7182\approx7182

The correct answer is 7182.\text{The correct answer is 7182.}