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Question: Given circles are x2 + y2 – 4x – 5 = 0 and x2 + y2 + 6x – 2y + 6 = 0 Let P be a point (a, b) such t...

Given circles are x2 + y2 – 4x – 5 = 0 and

x2 + y2 + 6x – 2y + 6 = 0 Let P be a point (a, b) such that the tangents from P to both the circles are equal. Then

A

2a + 10b + 11 = 0

B

2a - 10b + 11 = 0

C

10a - 2b + 11 = 0

D

10a + 2b + 11 = 0

Answer

10a - 2b + 11 = 0

Explanation

Solution

Point P lies on radical axis S1 – S2 = 0