Question

Given below are two statements :
Statement I : If the Brewster's angle for the light propagating from air to glass is $\theta_{ B }$, then the Brewster's angle for the light propagating from glass to air is $\frac{\pi}{2}-\theta_m$
Statement II : The Brewster's angle for the light propagating from glass to air is $\tan ^{-1}\left(\mu_{ g }\right)$ where $\mu_{ g }$ is the refractive index of glass
In the light of the above statements choose the correct answer from the options given below:

• A. Both Statement I and Statement II are true
• B. Both Statement I and Statement II are false
• C. Statement I is true but Statement II is false
• D. Statement I is false but Statement II is true

Answer 1

Answer: (C)

Statement I is true but Statement II is false

Answer 2

μa​sini1​=μg​sin(90−i1​)
tani1​=μa​μg​​
When going from glass to air
tani2​=μg​μa​​=coti1​
Hence
i2​=2π​−i1​