Question

Given below are two statements:
Statement I: Aniline reacts with con. $H_2SO_4$ followed by heating at 453–473 K gives p-aminobenzene sulphonic acid, which gives blood red colour in the 'Lassaigne's test'.
Statement II: In Friedel-Craft's alkylation and acylation reactions, aniline forms salt with the $AlCl_3$ catalyst. Due to this, nitrogen of aniline acquires a positive charge and acts as a deactivating group.
In the light of the above statements, choose the correct answer from the options given below:

• A. Statement I is false but Statement II is true
• B. Both Statement I and Statement II are false
• C. Statement I is true but Statement II is false
• D. Both Statement I and Statement II are true

Answer 1

Answer: (D)

Both Statement I and Statement II are true

Answer 2

Statement I is correct because aniline does react with concentrated sulfuric acid and, upon heating, forms p -aminobenzene sulfonic acid, which gives a blood red color in Tassaigne’s test.

Statement II is also correct as in Friedel-Crafts alkylation and acylation reactions, aniline forms a salt with the $\text{AlCl}_3$ catalyst. This interaction results in a positive charge on nitrogen, causing it to act as a deactivating group, making further substitution reactions difficult on the benzene ring.

Thus, both statements are true.