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Question: Given below are two statements: Statement I: A spherical ball under the surrounding pressure of 6 $...

Given below are two statements:

Statement I: A spherical ball under the surrounding pressure of 6 P0P_0 is brought to the surrounding of pressure P0P_0. If bulk modulus of ball is 100 P0P_0 then fractional change in volume of ball is 0.05

Statement II: For volumetric strain of 0.06 in a spherical ball the change in radius of ball is of magnitude of 2%.

In the light of above statements, choose the correct answer from the options given below.

A

Statement I is true and Statement II is true.

B

Statement I is true and Statement II is false.

C

Statement I is false and Statement II is true.

D

Statement I is false and Statement II is false.

Answer

Both Statement I and Statement II are correct.

Explanation

Solution

Statement I: The bulk modulus is B=ΔPΔV/VB = -\frac{\Delta P}{\Delta V/V}. Given initial pressure Pinitial=6P0P_{initial} = 6P_0, final pressure Pfinal=P0P_{final} = P_0, so ΔP=P06P0=5P0\Delta P = P_0 - 6P_0 = -5P_0. The bulk modulus is B=100P0B = 100P_0. Thus, ΔVV=ΔPB=5P0100P0=0.05\frac{\Delta V}{V} = -\frac{\Delta P}{B} = -\frac{-5P_0}{100P_0} = 0.05. Statement I is correct.

Statement II: For a sphere, V=43πr3V = \frac{4}{3}\pi r^3. For small changes, ΔVV3Δrr\frac{\Delta V}{V} \approx 3\frac{\Delta r}{r}. Given ΔVV=0.06\frac{\Delta V}{V} = 0.06, then 0.063Δrr0.06 \approx 3\frac{\Delta r}{r}, which gives Δrr0.02\frac{\Delta r}{r} \approx 0.02 or 2%2\%. Statement II is correct.