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Question

Mathematics Question on Sum of First n Terms of an AP

Given below are two statements, one is labelled as Assertion A and the other is labelled as Reason R
Assertion (A) : (1) +(1+2+4)+(4+6+9)+(9+12+16)++(81+90+100)=1000+(1+2+4)+(4+6+9) +(9+12+16)+\ldots+(81+90+100)=1000

Reason (R) : r=1n(r3[r1]3)=n3\displaystyle \sum_{r=1}^{n}\left(r^{3}-[r-1]^{3}\right)=n^{3} for any natural number nn

In the light of the above statements, choose the correct answer from the options given below

A

Both (A) and (R) are true and (R) is the coll ect explanation of (A)

B

Both (A) and (R) are tiue but (R) is not the collect explanation of (A)

C

(A) is tme but (R) is false

D

(A) is false but (R) is true

Answer

Both (A) and (R) are true and (R) is the coll ect explanation of (A)

Explanation

Solution

Since,
1+(1+2+4)+(4+6+9)+(9+12+16)+...+(81+90+100)1+(1+2+4)+(4+6+9)+(9+12+16) +...+(81+90+100)
=1+(12+(2×1)+22)+(22+(2×3)+32)+(32= 1+\left(1^{2}+(2 \times 1)+2^{2}\right)+\left(2^{2}+(2 \times 3)+3^{2}\right)+\left(3^{2}\right.
+(3×4)+42)++(92+(9×10)+102)\left.+(3 \times 4)+4^{2}\right)+\ldots+\left(9^{2}+(9 \times 10)+10^{2}\right)
=r=110[(r1)2+r(r1)+r2]=\displaystyle \sum_{r=1}^{10}\left[(r-1)^{2}+r(r-1)+r^{2}\right]
=r=110[r(r1)][(r1)2+r(r1)+r2]=\displaystyle \sum_{r=1}^{10}[r-(r-1)]\left[(r-1)^{2}+r(r-1)+r^{2}\right]
=r=110[r3(r1)3]=\displaystyle \sum_{r=1}^{10}\left[r^{3}-(r-1)^{3}\right]
=(1303)+(2313)+(3323)++(10393)=\left(1^{3}-0^{3}\right)+\left(2^{3}-1^{3}\right)+\left(3^{3}-2^{3}\right)+\ldots+\left(10^{3}-9^{3}\right)
=10303=1000= 10^{3}-0^{3}=1000
So, both (A) and (R)( R ) are true and (R)( R ) is the correct explanation of (A)(A).