Question

Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): Experimental reaction of $CH_3Cl$ with aniline and anhydrous $AlCl_3$ does not give o and p-methylaniline.
Reason (R): The $–NH_2$group of aniline becomes deactivating because of salt formation with anhydrous $AlCl_3$ and hence yields m-methyl aniline as the product.
In the light of the above statements, choose the most appropriate answer from the options given below :

• A. Both (A) and (R) are true and (R) is the correct explanation of (A).
• B. Both (A) and (R) are true but (R) is not the correct explanation of (A).
• C. (A) is true, but (R) is false.
• D. (A) is false, but (R) is true.

Answer 1

Answer: (C)

(A) is true, but (R) is false.

Answer 2

Aniline does not undergo Friedel Craft reaction because the reagent $AlCl_3$ being electron deficient acts as a Lewis acid.

So, the correct option is (C): (A) is true, but (R) is false.