Question

Given below are two reactions of water with sodium and corbon dioxide. What is the nature of water in these reactions?

(i) $2Na + 2H_{2}O \rightarrow 2NaOH + H_{2}$

(ii) $6CO_{2} + 12H_{2}O \rightarrow C_{6}H_{12}O_{6} + 6H_{2}O + 6O_{2}$

• A. In (ii) water acts as an oxidizing agent and in (i) it acts as a reducing agent.
• B. In (I) water acts as an oxidizing agent while in (ii) it acts as a reducing agent.
• C. In both, (i) and (ii) hydrogen acts as an reducing agent.
• D. In both (i) and (ii) hydrogen acts as an oxidizing agent.

Answer 1

Answer: (B)

In (I) water acts as an oxidizing agent while in (ii) it acts as a reducing agent.

Answer 2

: With sodium metal water acts as an oxidizing agent and gets reduced to $H_{2},$ with $CO_{2}$water acts as a reducing agent and is oxidised to oxygen.