Question

Given below are the standard electrode potentials of few half cells the correct order of these metals in increasing reducing power will be

$K^{+}|K = - 2.93V,Ag^{+}|Ag = 0.80V,$

$Mg^{2 +}|Mg = - 2.37V,Cr^{3 +}|Cr = - 0.74V$

• A. $K < Mg < Cr < Ag$
• B. $Ag < Cr < Mg < K$
• C. $Mg < K < Cr < Ag$
• D. $Cr < Ag < Mg < K$

Answer 1

Answer: (B)

$Ag < Cr < Mg < K$

Answer 2

Higher the oxidation potential more easily it is oxidized and hence greater is the reducing power hence increasing order of reducing power is

$Ag < Cr < Mg < K$