Question

Given below are few reactions with some expressions. Mark the expression which is not correctly matched.

• A. For concentration cell, $Ag|Ag^{+}(C_{1})||Ag^{+}(C_{2})|Ag;E_{cell} = - \frac{0.0591}{1}\log\frac{C_{1}}{C_{2}}$
• B. For the cell$2Ag^{+} + H_{2}(1atm) \rightarrow 2Ag + 2H^{+}(1M);$ $E_{cell} = Eº_{Cell} - \frac{0.0591}{2}\log\frac{\lbrack Ag^{+}\rbrack^{2}}{\lbrack H^{+}\rbrack^{2}}$
• C. For an electrochemical reaction at equilibrium $aA + bB$ cC + dD ; $Eº_{cell} = \frac{0.0591}{n}\log\frac{\lbrack C\rbrack^{c}\lbrack D\rbrack^{d}}{\lbrack A\rbrack^{a}\lbrack B\rbrack^{b}}$
• D. For the cell $M_{(aq)}^{n +} + ne^{-} \rightarrow M_{(s)}$ $E_{cell} = Eº - \frac{0.0591}{n}\log\frac{1}{\lbrack M^{n +}\rbrack}$

Answer 1

Answer: (B)

For the cell$2Ag^{+} + H_{2}(1atm) \rightarrow 2Ag + 2H^{+}(1M);$

$E_{cell} = Eº_{Cell} - \frac{0.0591}{2}\log\frac{\lbrack Ag^{+}\rbrack^{2}}{\lbrack H^{+}\rbrack^{2}}$

Answer 2

For $2Ag^{+} + H_{2}(1atm) \rightarrow 2Ag + 2H^{+}(1M)$

$E_{cell} = Eº_{cell} - \frac{0.0591}{2}\log\frac{\lbrack H^{+}\rbrack^{2}}{\lbrack Ag^{+}\rbrack^{2}}$