Question

Given,${B_2}{H_6} + N{H_3} \to$ Addition Compound $(X)$
$(X)\xrightarrow{{450K}}Y + Z(g)$
In the above sequence $Y$ and $Z$ are respectively:
A.Borazine, ${H_2}O$
B.Boron, ${H_2}$
C.Boron nitride, ${H_2}$
D.Borazine and hydrogen

Answer 1

The given reaction is the sequential reaction. The reactants of the reaction are diborane and ammonia. Diborane is a chemical compound consisting of boron and hydrogen with a molecular formula ${B_2}{H_6}$.

Complete step by step answer:
Now we will discuss the basic meaning of sequential reaction. A reaction is said to be sequential only when the product of the first reaction acts as a substrate for the next reaction. Now we will understand the reaction step by step and then we will predict the unknown compounds of the reaction. So, the overall reaction can be written as given below.
${B_2}{H_6} + 2N{H_3} \to {B_2}{H_6}.2N{H_3}$
$3{B_2}{H_6}.2N{H_3}\xrightarrow{{450K}}2{B_3}{N_3}{H_6} + 3{H_2}$
So, the above reaction is balanced. Now we will try to understand the flow of the reaction. So, in the first step of the sequential reaction diborane reacts with ammonia to give an additional compound $(X)$ which is ${B_2}{H_6}.2N{H_3}$. Now after that in the next reaction we will heat the additional compound formed at a temperature of $450K$. When the additional compound is heated at a given temperature $Y$ and $Z$ is formed. So, according to our reactions when the additional compound ${B_2}{H_6}.2N{H_3}$ is heated at a given temperature borazine and hydrogen are formed. In the given reaction in question, we have given that $Z$ is a gas. So, hydrogen gas will be $Z$ and borazine will be $Y$. Hence, $Y \to {B_3}{N_3}{H_6}$ and $Z \to {H_2}$.
Therefore, the correct option is (D) borazine and hydrogen.

Note:
The additional compound ${B_2}{H_6}.2N{H_3}$ formed is commonly known as inorganic benzene. The inorganic benzene ${B_2}{H_6}.2N{H_3}$ is the ionic product. The common name of Borazine formed is borazole. The compound is isoelectronic and isostructural with benzene.