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Question: Given a reaction: \(SiC{l_4}\xrightarrow{{{H_2}O}}\left( A \right)\xrightarrow{\Delta }\left( B \r...

Given a reaction:
SiCl4H2O(A)Δ(B)heatNa2CO3(C)SiC{l_4}\xrightarrow{{{H_2}O}}\left( A \right)\xrightarrow{\Delta }\left( B \right)\xrightarrow[{heat}]{{N{a_2}C{O_3}}}\left( C \right). The compound C is:
A.SiO2Si{O_2}
B.SiSi
C.SiCSiC
D.Na2SiO3N{a_2}Si{O_3}

Explanation

Solution

We know that silicon tetrachloride is a covalent chloride. It appears as a colourless liquid at room temperature that fumes in air that is moist. Silicon chloride does not conduct electricity due to the absence of electrons (or) ions. Ionic chlorides generally dissolve in water whereas other chlorides react with water in several ways.

Complete step by step answer:
We have to know that the silicon chloride is an example of covalent chloride. We have to know there isn’t much difference in electronegativity between the atom of silicon and atom of chlorine to give ionic bonds.
Chloride of period three on reaction with water forms metal hydroxide and it is a hydrolysis reaction. Silicon tetrachloride reacts with water and it forms silicon hydroxide. So, we can write the chemical reaction as,
SiCl4H2OSi(OH)2SiC{l_4}\xrightarrow{{{H_2}O}}Si{\left( {OH} \right)_2}
The product A is silicon hydroxide and its formula is Si(OH)2Si{\left( {OH} \right)_2}.
Hydroxides generally on heating form their respective oxides. Silicon hydroxide on heating gives silicon dioxide. So, we can write the reaction as,
Si(OH)2ΔSiO2Si{\left( {OH} \right)_2}\xrightarrow{\Delta }Si{O_2}
The product B is silicon dioxide and its formula is SiO2Si{O_2}.
The metallic oxide on reaction with sodium carbonate on heating gives sodium salt of the metallic oxide. Silicon dioxide on reaction with sodium carbonate by heating forms the product sodium metasilicate. So, we can write the chemical reaction as,
SiO2Na2CO3Na2SiO3+CO2Si{O_2}\xrightarrow{{N{a_2}C{O_3}}}N{a_2}Si{O_3} + C{O_2}
The product C is sodium metasilicate.
We can write the completed equation as,
SiCl4H2OSi(OH)2ΔSiO2heatNa2CO3Na2SiO3SiC{l_4}\xrightarrow{{{H_2}O}}Si{\left( {OH} \right)_2}\xrightarrow{\Delta }Si{O_2}\xrightarrow[{heat}]{{N{a_2}C{O_3}}}N{a_2}Si{O_3}
The product C is Na2SiO3N{a_2}Si{O_3} and Option (D) is correct.

Note:
We must remember that the sodium metasilicate is the chief substance of commercial sodium silicate solutions. It is an ionic compound that contains sodium cations and polymeric metasilicate anions. It appears as solid that is soluble in water whereas insoluble in alcohols. We can use it in cements and binders, automotive applications, and crafts.