Question

Given (A) $n=5, m_{\ell} =+1$ (B) $n=2, \ell=1, m_{\ell} =1, m_{s} =-\frac{1}{2}$ The maximum number of electron(s) in an atom that can have the quantum numbers as given in (A) and (B) are respectively:

• A. 25 and 1
• B. 8 and 1
• C. 2 and 4
• D. 4 and 1

Answer 1

Answer: (B)

8 and 1

Answer 2

The correct option is(B): 8 and 1.

(i) n = 5 means 1= 0,1,2,3,4 since m = + 1

hence

total no. of electrons will be

=0 (from s) + 2 (from p) + 2 (from d) + 2 (from f) + 2 (from g)

= 0 + 2 + 2 + 2 + 2 = 8

(ii) n=2, l=1, $m_{t}=1, m_{s} =$ $\frac{1}{2}$ represent
2p orbital with one electron